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A mountain climber stands at the top of a 41.5-m cliff that overhangs a calm pool...

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Physics

A mountain climber stands at the top of a 41.5-m cliff thatoverhangs a calm pool of water. She throws two stones verticallydownward 1.00 s apart and observes that they cause a single splash.The first stone had an initial velocity of -1.40 m/s. (Indicate thedirection with the sign of your answer.)

(a) How long after release of the first stone did the two stoneshit the water? (Round your answer to at least two decimalplaces.)
s

(b) What initial velocity must the second stone have had, giventhat they hit the water simultaneously?
m/s

(c) What was the velocity of each stone at the instant it hit thewater?

first stone    m/s
second stone    m/s

Answer & Explanation Solved by verified expert
3.7 Ratings (521 Votes)
Using 3rd kinematic equation for 1st stone v12 u12 2ad u1 initial speed of 1st stone 140 msec Weve assumed that downward direction is negative So a 981 msec2 d vertical distance of pool 415 m v1 sqrt u12    See Answer
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