A mixture is made by combining 11.5 mL of 8.5×10−3 M KSCN, 6.3 mL of 3.7×10−2...

Free

70.2K

Verified Solution

Question

Chemistry

A mixture is made by combining 11.5 mL of 8.5×10−3 M KSCN, 6.3mL of 3.7×10−2 M Fe(NO3)3, and 10.4 mL of 0.397 M HNO3. Calculatethe concentraion of Fe3+ in the solution.

Answer & Explanation Solved by verified expert
4.3 Ratings (679 Votes)

number of moles of KSCN = ((8.5 * 10^-3) * 11.5) / 1000 = 9.775 * 10^-5

number of moles of Fe(NO3)3 = ((3.7*10^-2)*10.4) / 1000 = 3.848 * 10^-4

3 KSCN (aq) + Fe(NO3)3 (aq) ---------> Fe(SCN)3 (s) + 3 KNO3 (aq)

3 mole of KSCN requires 1 mole of Fe(NO3)3

9.775 * 10^-5 moles of KSCN requires (1/3) * 9.775 * 10^-5

                                                                     = 3.2583 * 10^-5 moles

remaining moles of Fe(NO3)3 = (3.848 * 10^-4) - (3.2583 * 10^-5) = 3.5222 * 10^-4

concentration of Fe+3 = (3.5222 * 10^-4) * (1000 / (11.5 + 6.3 + 10.4))

                                       = 0.01249 M


Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:
  • Unlimited Question Access with detailed Answers
  • Zin AI - 3 Million Words
  • 10 Dall-E 3 Images
  • 20 Plot Generations
  • Conversation with Dialogue Memory
  • No Ads, Ever!
  • Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!
Become a Member

Other questions asked by students