A mixture containing an initial concentration of 0.1726 M for H2 and 0.1361 M for I2...

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A mixture containing an initial concentration of 0.1726 M for H2and 0.1361 M for I2 is allowed to come to equilibrium (see reactionbelow). What must be the equilibrium concentration of HI? H2(g) +I2(g) â†” 2HI(g) Kc = 48.7000
0.0726 M
0.0582 M
0.1164 M
0.2327 M

Answer & Explanation Solved by verified expert

4.3 Ratings (528 Votes)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â H₂(g)Â Â + Â Â I₂(g) Â Â â†”Â Â 2HI(g)

initial conc.Â Â Â Â Â Â Â Â Â 0.1726Â Â Â Â Â Â Â Â 0.1361Â Â Â Â Â Â Â Â Â 0

changeÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â -aÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â -aÂ Â Â Â Â Â Â Â Â Â Â Â Â +2a

Equb concÂ Â Â Â Â Â Â 0.1726-aÂ Â Â Â Â Â 0.1361-aÂ Â Â Â Â Â Â 2a

Equilibrium constant , K_c = [HI(g)]² / ([H₂(g)][I₂(g)] )

K_c = 48.7000 = (2a)² / [(0.1726-a)(0.1361-a)]

Solving we get a = 0.1164M

Therefore the equilibrium concentration of HI = 2a

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 2 x 0.1164 M

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 0.2327 M

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A mixture containing an initial concentration of 0.1726 M for H2 and 0.1361 M for I2...

Free

70.2K

Verified Solution

Question

Chemistry

A mixture containing an initial concentration of 0.1726 M for H2and 0.1361 M for I2 is allowed to come to equilibrium (see reactionbelow). What must be the equilibrium concentration of HI? H2(g) +I2(g) â†” 2HI(g) Kc = 48.7000
0.0726 M
0.0582 M
0.1164 M
0.2327 M

Answer & Explanation Solved by verified expert

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A mixture containing an initial concentration of 0.1726 M for H2 and 0.1361 M for I2...

Free

70.2K

Verified Solution

Question

Chemistry

A mixture containing an initial concentration of 0.1726 M for H2and 0.1361 M for I2 is allowed to come to equilibrium (see reactionbelow). What must be the equilibrium concentration of HI? H2(g) +I2(g) â†” 2HI(g) Kc = 48.70000.0726 M0.0582 M0.1164 M0.2327 M

Answer & Explanation Solved by verified expert

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A mixture containing an initial concentration of 0.1726 M for H2and 0.1361 M for I2 is allowed to come to equilibrium (see reactionbelow). What must be the equilibrium concentration of HI? H2(g) +I2(g) â†” 2HI(g) Kc = 48.7000
0.0726 M
0.0582 M
0.1164 M
0.2327 M