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A merry-go-round with a a radius of R = 1.98 m and moment of inertia I...

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Physics

A merry-go-round with a a radius of R = 1.98 m and moment ofinertia I = 193 kg-m2 is spinning with an initialangular speed of ω = 1.45 rad/s in the counter clockwise direectionwhen viewed from above. A person with mass m = 67 kg and velocity v= 4.9 m/s runs on a path tangent to the merry-go-round. Once at themerry-go-round the person jumps on and holds on to the rim of themerry-go-round.

1) What is the magnitude of the initial angular momentum of themerry-go-round?

2) What is the magnitude of the angular momentum of the person 2meters before she jumps on the merry-go-round?

3) What is the magnitude of the angular momentum of the personjust before she jumps on to the merry-go-round?

4) What is the angular speed of the merry-go-round after theperson jumps on?

5) Once the merry-go-round travels at this new angular speed,with what force does the person need to hold on?

6) Once the person gets half way around, they decide to simplylet go of the merry-go-round to exit the ride.

What is the magnitude of the linear velocity of the person rightas they leave the merry-go-round?

7) What is the angular speed of the merry-go-round after theperson lets go?

PLEASE ANSWER CORRECTLY WILL GIVE A THUMBS UP

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