A mass of 8 kg rests on a floor with a coefficient of static friction of...

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Physics

A mass of 8 kg rests on a floor with a coefficient of staticfriction of 0.88 and coefficient kinetic friction of 0.33. Oneforce is applied vertically downward of 28 Newtons and anotherforce is applied at an angle of 26 degrees below the horizontal.Calculate what the magnitude this force needs to be in order tobegin to move the mass. If that force is removed and another forceis applied at an angle of 26 degrees above the horizontal (thedownward force is still there), calculate the force needed to beginto move the force for that situation. How much more force is neededto begin the mass, in Newtons, when the force is angled below thehorizontal compared to above the horizontal?

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4.1 Ratings (495 Votes)
Given mass 8kg 088 and 033Vertical force 28NCase 1 Force F acting at an angle 26 deg BELOW thehorizontalLets split force F into its componentsFx Fcos 26 acting in ve x directionFy Fsin26 acting downwards in ve y    See Answer
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