A mass of 11.0 kg , fastened to the end of an aluminum wire with an...
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Physics
A mass of 11.0 kg , fastened tothe end of an aluminum wire with an unstretched length of 0.47 m ,is whirled in a vertical circle with a constant angular speed of118 rev/min . The cross-sectional area of the wire is2.0×10−2 cm2.
Part A:
Calculate the elongation of the wire when the mass is at thelowest point of the path.
Express your answer using two significant figures.
Part B:
Calculate the elongation of the wire when the mass is at thehighest point of its path.
Express your answer using two significant figures.
A mass of 11.0 kg , fastened tothe end of an aluminum wire with an unstretched length of 0.47 m ,is whirled in a vertical circle with a constant angular speed of118 rev/min . The cross-sectional area of the wire is2.0×10−2 cm2.
Part A:
Calculate the elongation of the wire when the mass is at thelowest point of the path.
Express your answer using two significant figures.
Part B:
Calculate the elongation of the wire when the mass is at thehighest point of its path.
Express your answer using two significant figures.
Answer & Explanation Solved by verified expert
Calculate the elongation of the wire when the mass is at the highest point of its path.
Express your answer using two significant figures.
  angular velocity   ω   =   118 rev/s   =   118 * 2π  rad/s
                                       =   741.4      rad/s Â
   Centrifugal force   Fc  =  m * r * ω2
                                       =   11 * 0.47 * 741.42
                                       =   2841936.00N
   Net force   F   =   Fc + m * g
                           =   2841936.00+   11 * 9.8
                           =   2842043.8 N
   Young's modulus is defined as
   Y   =   F * L / A * ΔL
   Where ΔL is elongation produced and L = r = length of wire
   ΔL   =   F * L / A * Y
   =>   ΔL   =   2842043.8* 0.47/ 2.0 * 10-6 * 2.0 * 1011
                 =   3.3 * 10-3  m
                  =   3.3   mm
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