A manufacturer wants to compare the number of defects on the day shift with the number...

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A manufacturer wants to compare the number of defects on the dayshift with the number on the evening shift. A sample of productionfrom recent shifts showed the following defects: Day Shift 5 8 7 69 7

Evening Shift 8 10 7 11 9 12 14 9

The objective is to determine whether the mean number of defectson the night shift is greater than the mean number on the day shiftat the 95% confidence level.

State the null and alternate hypotheses.

What is the level of significance? What is the test statistic?What is the decision rule? Use the Excel Data Analysis pack toanalyze the problem. Include the output with your answer. (Note:You may calculate by hand if you prefer). What is your conclusion?Explain. Does the decision change at the 99% confidence level?

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4.1 Ratings (797 Votes)
Ho 1 2 0 Ha 12 DAY mean of sample 1 x1 700 standard deviation of sample 1 s1 141 size of    See Answer
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