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A man is heterozygous for achondroplasia for which the autosomal dominant A allele confers extremely short...

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Biology

A man is heterozygous for achondroplasia for which the autosomaldominant A allele confers extremely short stature. His wife'sgenotype is aa and she is normal height. They have five childrentogether. What is the probability that any two of their fivechildren will have the short stature phenotype, in any birthorder?

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solution The probability is 516 that any two of their five children will have the short stature phenotype Explanation As man is heterozygous for achondroplasia Aa and and his wife has    See Answer
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