A major leaguer hits a baseball so that it leaves the bat at aspeed of 31.9 m/s and at an angle of 35.6 ∘ above the horizontal.You can ignore air resistance.At what two times is the baseball ata height of 10.2 m above the point at which it left the bat? Giveyour answers in ascending order separated with comma. t1,t2 = sPrevious AnswersRequest Answer Incorrect; Try Again; 2 attemptsremaining Part BPart complete Calculate the horizontal component ofthe baseball's velocity at an earlier time calculated in part (a).vx = 25.9 m/s Previous Answers Correct Part C Calculate thevertical component of the baseball's velocity at an earlier timecalculated in part (a). vy = m/s Previous AnswersRequest AnswerIncorrect; Try Again; 2 attempts remaining Part D Calculate thehorizontal component of the baseball's velocity at a later timecalculated in part (a). vx = nothing m/s Request Answer Part ECalculate the vertical component of the baseball's velocity at alater time calculated in part (a). vy = nothing m/s Request AnswerPart F

What is the magnitude of the baseball's velocity when it returnsto the level at which it left the bat?

vv =	nothing	m/sm/s

SubmitRequest Answer

Part G

What is the direction of the baseball's velocity when it returnsto the level at which it left the bat?

magnitude of the baseball's velocity when it returns to thelevel at which it left the bat? v = nothing m/s Request Answer PartG What is the direction of the baseball's velocity when it returnsto the level at which it left the bat? θ = nothing ∘ below thehorizontal Request Answer Provide Feedback