(a) If the molar solubility of Cd3(PO4)2 at 25 oC is 1.19e-07 mol/L, what is the...

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Chemistry

(a) If the molar solubility of Cd3(PO4)2 at 25 oC is 1.19e-07mol/L, what is the Ksp at this temperature?

Ksp =

(b) It is found that 0.00178 g of Ag3PO4 dissolves per 100 mL ofaqueous solution at 25 oC. Calculate the solubility-productconstant for Ag3PO4.

Ksp =

(c) The Ksp of Sc(OH)3 at 25 oC is 2.22e-31. What is the molarsolubility of Sc(OH)3?

solubility ________= mol/L

Answer & Explanation Solved by verified expert
4.1 Ratings (564 Votes)

Cd3(PO4)2 -------------> 3Cd+2 + 2PO43-

                                        3s           2s

Ksp = [Cd+2]3[PO43-]2

        =   (3s)3 (2s)2

          = 108s5

         = 108*(1.19*10-7)5

          = 2.57*10-33

b. solubility = W*1000/G.M.Wt * volume of solution in ml

                     = 0.00178*1000/418.58*100

                      = 4.25*10-5

   Ag3(PO4) ----------> 3Ag+   + PO43-

                                   3s           s

Ksp   = [Ag+]3 [PO43-]

          = (3s)3 *s

          = 27s4

          = 27*(4.25*10-5)4

          = 8.8*10-17

c.   Sc(OH)3 --------> Sc+3 + 3OH-

                                  s          3s

   Ksp = [Sc+3][OH-]3

           = s*(3s)3

   2.22*10-31       = 27s4

    0.82*10-32    = s4

       s     = 9.5*10-9 mole/L


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