a) How many moles ofAl2(SO4)3 arerequired to make 45 mL of a 0.080 MAl2(SO4)3 solution?
(Hint, molarity is moles per liter. You know the molarity. Youare given the number of mL's, which can be converted to liters.Just set it up so the units cancel and you get \"moles\".)
_____________ molesAl2(SO4)3
b) What is the molar mass ofAl2(SO4)3, to thenearest gram?
_____________ [grams/mole]
c) What mass ofAl2(SO4)3 isrequired to make 45 mL of a 0.080 MAl2(SO4)3 solution?
(If you've got moles and molecular weight you can get tograms.)
______________ g Al2(SO4)3
d) How many moles of aluminumions are present in the solution?
(This is easy. You know how many moles ofAl2(SO4)3 there are from part a.Just think about how many aluminum ions there are perAl2(SO4)3.)
______________ mol
