a) How many moles of Al2(SO4)3 are required to make 45 mL of a 0.080 M Al2(SO4)3 solution? (Hint,...

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Chemistry

a) How many moles ofAl₂(SO₄)₃ arerequired to make 45 mL of a 0.080 MAl₂(SO₄)₃ solution?
(Hint, molarity is moles per liter. You know the molarity. Youare given the number of mL's, which can be converted to liters.Just set it up so the units cancel and you get \"moles\".)
_______ molesAl₂(SO₄)₃

b) What is the molar mass ofAl₂(SO₄)₃, to thenearest gram?
_ [grams/mole]

c) What mass ofAl₂(SO₄)₃ isrequired to make 45 mL of a 0.080 MAl₂(SO₄)₃ solution?
(If you've got moles and molecular weight you can get tograms.)
g Al₂(SO₄)₃

d) How many moles of aluminumions are present in the solution?
(This is easy. You know how many moles ofAl₂(SO₄)₃ there are from part a.Just think about how many aluminum ions there are perAl₂(SO₄)₃.)
______ mol

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3.6 Ratings (494 Votes)

Ans a Molarity number of moles of solutes per L of solution moles L Also number of moles in a solution Molarity x volume in L of the solution Or moles L x L moles See Answer

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