A group of physicians from Denmark conducted a year-long study of the effectiveness of nicotine chewing...

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A group of physicians from Denmark conducted a year-long studyof the effectiveness of nicotine chewing gum in helping people stopsmoking. The 113 people who participated in the study were allsmokers. Of these, 60 were given a chewing gum with 2 mg ofnicotine, and 53 were given a placebo chewing gum with no nicotine.This was a randomized controlled study. All were told to use thegum and refrain from smoking. Results showed that 23 of the smokersgiven the nicotine chewing gum had remained nonsmokers for the1-year period while 12 of the smokers given the placebo hadremained nonsmokers during the same period. Do these resultssupport the conclusion that nicotine gum can help stop smoking?Test at α = 0.05.

1-Hypothesis test for one population mean (unknown populationstandard deviation)

2-Confidence interval estimate for one population mean (unknownpopulation standard deviation)

3-Hypothesis test for population mean from paireddifferences

4-Confidence interval estimate for population mean from paireddifferences

5-Hypothesis test for difference in population means from twoindependent samples

6-Confidence interval estimate for difference in populationmeans from two independent samples

7-Hypothesis test for one population proportion

8-Confidence interval estimate for one population proportion

9-Hypothesis test for difference between two populationproportions

10-Confidence interval estimate for difference between twopopulation proportions

In developing patient appointment schedules, a medical centerwants to compare the mean time that staff members spend withpatients between two offices--one in Cleveland and one inCincinnati. A random sample of 30 office visits is taken from eachoffice. Estimate the difference with a 95% level of confidence.

1-Hypothesis test for one population mean (unknown populationstandard deviation)

2-Confidence interval estimate for one population mean (unknownpopulation standard deviation)

3-Hypothesis test for population mean from paireddifferences

4-Confidence interval estimate for population mean from paireddifferences

5-Hypothesis test for difference in population means from twoindependent samples

6-Confidence interval estimate for difference in populationmeans from two independent samples

7-Hypothesis test for one population proportion

8-Confidence interval estimate for one population proportion

9-Hypothesis test for difference between two populationproportions

10-Confidence interval estimate for difference between twopopulation proportions

Answer & Explanation Solved by verified expert
4.5 Ratings (976 Votes)

Correct option is:

5-Hypothesis test for difference in population means from two independent samples

below are test details:

null Hypothesis:    Ho:    p1-p2 = 0.00
alternate Hypothesis: Ha:   p1-p2 > 0.00
for 0.05 level with right tailed test , critical value of z= 1.645
Decision rule :                   reject Ho if test statistic z > 1.645
treatment Placebo
x1                =    23 x2                =    12
p̂1=x1/n1 = 0.3833 p̂2=x2/n2 = 0.2264
n1                       = 60 n2                       = 53
estimated prop. diff =p̂1-p̂2    = 0.1569
pooled prop p̂ =(x1+x2)/(n1+n2)= 0.3097
std error Se=√(p̂1*(1-p̂1)*(1/n1+1/n2) = 0.0872
test stat z=(p̂1-p̂2)/Se = 1.80
since test statistic falls in rejection region we reject null hypothesis
we have sufficient evidence to conclude that nicotine gum can help stop smoking

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