A Geiger tube consists of two elements, a long metal cylindrical shell and a long straight...

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Physics

A Geiger tube consists of two elements, a long metal cylindricalshell and a long straight metal wire running down its central axis.Model the tube as if both the wire and cylinder are infinitelylong. The central wire is positively charged and the outer cylinderis negatively charged. The potential difference between the wireand the cylinder is 1.10 kV. Suppose the cylinder in the Geigertube has an inside diameter of 3.64 cm and the wire has a diameterof 0.452 mm. The cylinder is grounded so its potential is equal tozero.
(a) What is the radius of the equipotential surface that has apotential equal to 545 V? Is this surface closer to the wire or tothe cylinder?
(b) How far apart are the equipotential surfaces that havepotentials of 195 and 245 V?
(c) Compare your result in Part (b) to the distance between thetwo surfaces that have potentials of 685 and 730 V,respectively.
What does this comparison tell you about the electric fieldstrength as a function of the distance from the central wire?

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3.9 Ratings (498 Votes)

Inner radius of the cylinder is rc 3642 182cm and the radius of wire is rw 04522 0226 mmThus the radial distance between cylinder and wire isThe given potential difference between cylinder and wire isVd 110 kV See Answer

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