apply the relation between force and accleration as F=
ma
where m is mass
a is accleration and
F is force
so as we need
part A: accleration a = F/m
a = 126/27
a = 4.667 m/s^2
------------<<<<<<<<<<<<<<<
-------------------------------------
part B :
use the kinematic equation S = ut + 0.5
at^2
where a is accleration  = 4.67
m/s^2
t is time = 10.5 secs
as it starts from rest initial velocity u =Ă‚Â Ă‚Â
0
so
S = x =Ă‚Â Ă‚Â distance travelled = 0.5 * 4.67 *
10.5 *10.5
x  = 257.44
meters------------<<<<<<<<<<<<<<<
-----------------------------------------------
part C:
use again the Kinematic equation V = u + at
V = 0 + (4.67* 10.5)
V = 49.035
m/s----------------------<<<<<<<<<<<<<<<<
