A concentration cell based on the following half reaction at 312 k ag+ + e- -------->...

Free

90.2K

Verified Solution

Question

Chemistry

A concentration cell based on the following half reaction at 312k ag+ + e- --------> ag srp = 0.80 v has initial concentrationsof 1.25 m ag+, 0.221 m ag+, and a potential of 0.04865 v at theseconditions. after 8.3 hours, the new potential of the cell is foundto be 0.01323 v. what is the concentration of ag+ at the cathode atthis new potential? Please explain all the steps used to find theanswer.

Answer & Explanation Solved by verified expert

4.0 Ratings (451 Votes)

The quantitative relationship between electrolyte concentration and cell potential is given by the following Nernst Equation:Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â E_cell = E^o_cell - (RT/nF) lnQ;Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â

E_cell is cell potential under non-standard conditions, while E^o_cell is cell potential under standard conditions (calculated from standard reduction potentials), R = 8.314 J/(mol.K), F = 96,485 C/mol, is the Faradayâ€™s constant; Q is the reaction quotient.

For the given half cell Ag⁺ + e^- = Ag,

Q = 1/ [Ag⁺] , E^o_cell = 0.80V, T= 312K, n=1

E_cell = E^o_cell - (RT/nF) lnQ;

Â Â Â Â Â Â Â = 0.8 - (8.314)(312)/96500 [ln(1/ [Ag⁺] )]

0.01323 v = 0.8v - 0.0268[ln(1/[X])

Â Â Â Â [log(1/[X]) = 29.4

Â Â Â Â Â Â Â 1/x = 10^-29.4

^{Â Â Â Â Â Â Â Â Â} X = 1/10^-29.4

^{Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â}

Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:

Unlimited Question Access with detailed Answers
Zin AI - 3 Million Words
10 Dall-E 3 Images
20 Plot Generations
Conversation with Dialogue Memory
No Ads, Ever!
Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!

Become a Member