a. Compute the energy of a photon with incident energy 200 kev scattered at 90Â° in a...

Free

90.2K

Verified Solution

Question

Physics

a. Compute the energy of a photon with incident energy 200 kevscattered at 90Â°
in a Compton event.
b. Compute the energy of the backscattered photon from a 400 kevincident
photon.
c. Compute the energy of the recoil electron.

Answer & Explanation Solved by verified expert

3.9 Ratings (789 Votes)

a) let lamda is the wavelength of the incident photon.

use, E = h*c/lamda

lamda = h*c/E

= 6.626*10^-34*3*10^8/(200*10^3*1.6*10^-19)

= 6.21*10^-12 m

wavelength of scattered photon,

lamda' = lamda + (h/(m*c))*(1 - cos(theta))

= 6.21*10^-12 + (6.626*10^-34/(9.1*10^-31*3*10^8))*(1 - cos(90))

= 8.64*10^-12 m

Energy of scattered photon, E' = h*c/lamda'

= 6.626*10^-34*3*10^8/(8.64*10^-12)

= 2.30*10^-14 J

= 2.30*10^-14/(1.6*10^-19)

= 143.7 keV

b) lamda = h*c/E

= 6.626*10^-34*3*10^8/(400*10^3*1.6*10^-19)

= 3.11*10^-12 m

wavelength of scattered photon,

lamda' = lamda + (h/(m*c))*(1 - cos(theta))

= 3.11*10^-12 + (6.626*10^-34/(9.1*10^-31*3*10^8))*(1 - cos(180))

= 7.96*10^-12 m

Energy of scattered photon, E' = h*c/lamda'

= 6.626*10^-34*3*10^8/(7.96*10^-12)

= 2.49*10^-14 J

= 2.49*10^-14/(1.6*10^-19)

= 155.6 keV <<<<<<<<<------------Answer

c) Energy of the recoil electron = 400 - 155.6

= 244.4 keV <<<<<<<<<------------Answer

Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:

Unlimited Question Access with detailed Answers
Zin AI - 3 Million Words
10 Dall-E 3 Images
20 Plot Generations
Conversation with Dialogue Memory
No Ads, Ever!
Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!

Become a Member