A communications satellite is in a synchronous orbit that is 3.61Ã—107 m directly above the equator....

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A communications satellite is in a synchronous orbit that is3.61Ã—107 m directly above the equator. The satellite is locatedmidway between Quito, Equador, and Belem, Brazil, two cities almoston the equator that are separated by a distance of 3.87Ã—106 m.Calculate the time it takes for a telephone call to go by way ofsatellite between these cities. Ignore the curvature of theearth.

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4.3 Ratings (676 Votes)

The total distance traveled by signal is s.
So that the distance between Belem (or Quito) to satellite iss / 2 .
Therefore we can write
Â Â Â s / 2 = âˆš [ (h)² + (d / 2)² ]
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = âˆš [ (3.61 x 10⁷)² + (3.87x 10⁶ / 2)² ]
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 3.615 x 10⁷ m
Â Â Â Â Â Â Â Â ==>Â Â Â Â Â Â s = 7.23 x10⁷ m
The time taken by electromagnetic wave to travel a totaldistance s is
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â t = s / c
Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 7.23 x 10⁷ / 3 x 10⁸
Â Â Â = 0.241 sec

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