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A coin will be tossed 5 times. The chance of getting exactly 2 heads among 5...

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Basic Math

A coin will be tossed 5 times.

The chance of getting exactly 2 heads among 5 tosses is %.

The chance of getting exactly 4 heads among 5 tosses is %.

A coin will now be tossed 10 times.

The chance of getting exactly 2 heads in the first fivetosses and exactly 4 heads in the last 5 tosses is BLANK%.

All answers must have three numbers following the decimal.

I just need the answer to the bolded on (where I put "BLANK"just provided the whole question in case it is needed)

Answer & Explanation Solved by verified expert
4.2 Ratings (729 Votes)

p = 0.5

n = 5

This is a binomial distribution

P(X = x) = 5Cx * 0.5x * (1 - 0.5)5-x

1) P(X = 2) = 5C2 * 0.52 * 0.53 = 0.3125 = 31.25%

2) P(X = 4) = 5C4 * 0.54 * 0.51 = 0.1563 = 15.63%

3) P(2 heads in first 5 and 4 heads in next 5) = P(X = 2) * P(X = 4)

                                                                        = 0.3125 * 0.1563

                                                                        = 0.0488

                                                                        = 4.88% (ans)
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