AgO miili moles = M x V ( in
L)Â Â Â Â Â Â Â where V = 225 ml =
0.225 L
                       Â
= ( 8 x 10^ -5) mmol/LÂ Â x (0.225 L)
                 Â
= 1.8 x 10^ -5
AgO moles = milli moles x 10^ -3 = 1.8 x 10^ -5 x 10^ -3
= 1.8 x 10^ -8
AgO mass = moles x molar mass of AgO
             Â
= 1.8 x 10^ -8 mol x 123.9 g/mol
             Â
= 2.2 x 10^ -6 g
           Â
= 2.2
ug                     Â
( since 1ug = 10^ -6g)
hence silver (II) oxide mass is 2.2
micrograms
