A charge Q = 24 nC is fixed in space at co-ordinate (0, 0). Another charge...

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Physics

A charge Q = 24 nC is fixed in space at co-ordinate (0, 0).Another charge q= 4 nC; of mass 0.07 kg, is placed at (d , 0) thenlet go where d = 10 nm. We need to find the speed of the charge q.Gravity should be ignored.

a) Find the potential energy U1 between the two charges when qis at (10 nm, 0). Number Units

b) Find the potential energy U2 between the two charges when qis at (d + r , 0) where d = 10 nm and r = 2 nm Number Units

c) Find the change in potential energy, ΔU = U2 - U1. NumberUnits

d) Do you expect ΔU to be positive or negative? PositiveNegative

e) Is mechanical energy conserved ? Yes No

f) Using the conservation of energy, find the speed of q afterit has moved a distance r = 2. Number Units

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