assume 100 % = 100 grams
K = 8.242 g
Al = 5.687 g
H = 5.099 g
O = 67.45 g
S = 13.52 g
find the mole ration and then divide the smallest
possible value and then calculate the empirical formula is as
follows
mole ratio =>
=>
KÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
Al                  Â
HÂ Â Â Â Â Â Â Â Â Â Â
 Â
OÂ Â Â Â Â Â Â Â Â Â Â Â Â
S
=> (8.242/39.089) (5.687/26.98)
(5.099/1)Â Â Â (67.45/16)Â Â Â Â
(13.52/32)
=>
0.2108Â Â Â Â Â Â Â Â Â Â Â Â
0.2108 Â Â 5.099 Â Â 4.2156 Â Â Â
0.4225
=> (0.2108/0.2108) (0.2108/0.2108) (5.099/0.2108)
(4.2156/0.02108) (0.4225/0.2108)
=>Â Â Â
1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
24 Â Â 20 Â Â 2
the empirical formula is as follows
=>
K1Al1H24O20S2
answer =>
KAlH24O20S2Â Â
 Â
