A bottle of milkmilk initially has a temperature of 7575degreesÂ°F. It is left to cool in a refrigerator that...

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Advance Math

A bottle of
milkmilk
initially has a temperature of
7575degreesÂ°F.
It is left to cool in a refrigerator that has a temperatureof
4545degreesÂ°F.
After 10 minutes the temperature of the
milkmilk
is
5757degreesÂ°F.
a. Useâ€‹ Newton's Law ofâ€‹ Cooling,
Upper T equals Upper C plus left parenthesis Upper T 0 minusUpper C right parenthesis e Superscript ktT=C+T0âˆ’Cektâ€‹,
to find a model for the temperature of the
milkmilkâ€‹,
Tâ€‹,
after t minutes.
T
â€‹=
Upper C plus left parenthesis Upper T 0 minus Upper C rightparenthesis e Superscript ktC+T0âˆ’Cekt
T
â€‹=
45 plus left parenthesis 30 right parenthesis e Superscriptnothing t45+(30)e t
left arrowâ†
Solve for k and enter the answer
â€‹(Round to four decimalâ€‹ places.)
b. What is the temperature of the
milkmilk
after 15â€‹ minutes?
Tequals=nothingdegreesÂ°F
â€‹(Type an integer. Round to nearestâ€‹ degree.)
c. When will the temperature of the
milkmilk
be
5252degreesÂ°â€‹F?
tequals=nothing
minutes

Answer & Explanation Solved by verified expert

3.6 Ratings (403 Votes)

Newtons law of cooling formula is expressed by Tt Ts To Ts ekt Where t time Tt temperature of the given body at time t Ts surrounding temperature To See Answer

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T	â€‹=	Upper C plus left parenthesis Upper T 0 minus Upper C rightparenthesis e Superscript ktC+T0âˆ’Cekt
T	â€‹=	45 plus left parenthesis 30 right parenthesis e Superscriptnothing t45+(30)e t	left arrowâ†	Solve for k and enter the answer
		â€‹(Round to four decimalâ€‹ places.)