A block of mass 2M sits at the bottom of a container and is completely submerged...

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Physics

A block of mass 2M sits at the bottom of a container and iscompletely submerged in a liquid. A second block of mass M sits ontop of the first block with no amount of it submerged in theliquid. The blocks are made of the same material and the ratio ofthe density of the blocks to liquid is ?b/?l = 0.80.

a) Draw a FBD of bottom block. Ensure accurate relative sizebetween the force vectors and clearly label each.
b) Starting from first principles, calculate the magnitude ofthe normal force from the container onto the bottom block andexpress your result as a simplified expression of knownquantities.
c) Calculate the acceleration vector needed to be given to thecontainer to cause the bottom block to begin to lose contact withthe container. Write your result in terms of known quantities.State any assumptions necessary.

Answer & Explanation Solved by verified expert

4.3 Ratings (614 Votes)

aHerewe have given the mass of the bottom at the bottomcompletely immersed in the liquid isAnd the mass of the block placed above the bottom block whichnot submerged in watreHerethe wieght of the smaller block at the top is exerteddownwards on the bottom block asThe wieght of the bottom block itself downwardsThe buoyant force on the bottom block upwardsThe normal force Contact See Answer

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