a. An aqueous solution is made by dissolving 18.4 grams of iron(III) bromide in 314 grams of...

50.1K

Verified Solution

Question

Chemistry

a. An aqueous solution is made by dissolving18.4 grams of iron(III) bromidein 314 grams of water.  

The molality of iron(III) bromide in the solutionis ________m.

b.In the laboratory you are asked to make a0.473 m chromium(II) acetatesolution using 425 grams ofwater.  

How many grams of chromium(II) acetate should youadd?  
_________ grams.

c. The boiling point of diethyl etherCH3CH2OCH2CH3is 34.50°C at 1 atmosphere. A nonvolatile,nonelectrolyte that dissolves in diethyl ether ischlorophyll.

If 10.38 grams of chlorophyll,C55H72MgN4O5(893.5 g/mol), are dissolved in236.2 grams of diethylether.

The molality of the solution is ______ m.

The boiling point of the solution is______ °C.

d. The freezing point of benzeneC6H6 is5.50°C at 1 atmosphere. A nonvolatile,nonelectrolyte that dissolves in benzene isDDT .  

If 14.38 grams of DDT,C14H9Cl5(354.5 g/mol), are dissolved in276.5 grams of benzene ...

The molality of the solution is _____ m.

The freezing point of the solution is _________°C.

Answer & Explanation Solved by verified expert
3.7 Ratings (565 Votes)
a An aqueous solution is made by dissolving 184 grams of ironIII bromide in 314 grams of water Number of moles of ironIII bromide 184 g 29556 gmol 0062 mol ironIII bromide molality of ironIII bromide number of moles solvent in Kg 0062 mol ironIII bromide 0314 kg 0197 m The molality of ironIII bromide in the solution is 0197 m bIn the laboratory you are asked to make a 0473 m chromiumII acetate solution    See Answer
Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:
  • Unlimited Question Access with detailed Answers
  • Zin AI - 3 Million Words
  • 10 Dall-E 3 Images
  • 20 Plot Generations
  • Conversation with Dialogue Memory
  • No Ads, Ever!
  • Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!
Become a Member

Other questions asked by students