A 74.0-kg bungee jumper steps off a bridge with a light bungee cord tied to her...

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Physics

A 74.0-kg bungee jumper steps off a bridge with a light bungeecord tied to her and to the bridge. The unstretched length of thecord is 14.0 m. The jumper reaches reaches the bottom of her motion40.0 m below the bridge before bouncing back. We wish to find thetime interval between her leaving the bridge and her arriving atthe bottom of her motion. Her overall motion can be separated intoan 14.0-m free-fall and a 26.0-m section of simple harmonicoscillation.

(a) For the free-fall part, what is the appropriate analysismodel to describe her motion.

-particle under constant angular acceleration

-particle under constantacceleration    

-particle in simple harmonic motion


(b) For what time interval is she in free-fall?s

(c) For the the simple harmonic oscillation part of the plunge, isthe system of the bungee jumper, the spring, and the Earth isolatedor non-isolated?

-isolated

-non-isolated    


(d) From your response in part (c) find the spring constant of thebungee cord.N/m

(e) What is the location of the equilibrium point where the springforce balances the gravitational force exerted on the jumper?
m below the bridge

(f) What is the angular frequency of the oscillation?rad/s

(g) What time interval is required for the cord to stretch by 26.0m?s

(h) What is the total time interval for the entire 40.0-m drop?s

Answer & Explanation Solved by verified expert
3.7 Ratings (510 Votes)
a For the free fall part we can model the jumper as aparticle under constant acceleration Since duringthat time the particle has only constant acceleration equal toacceleration due to gravityb The jumper will have free fall until when the cord    See Answer
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