Where m1 = Mass of first body
,=7.2kg.
m2 = Mass of second body,=19kg.
u1 = Initial velocity of first
body,=10m/s
u2 = Initial velocity of second
body,=5.4m/s
v1 = Final velocity of first
body,=?
v2 = Final velocity of second
body=5.4m/s.
it is a elastic collision.
so,m1u1+m2u2=m1v1+m2v2.
(7.2)(10)+(19)(5.4)=(7.2)(v1)+(19)(5.4).
174.6=7.2v1+102.6.
  7.2v1=174.6-102.6
    :.v1=72/7.2
   :.v1=10m/s.
2.change in kinetic energy is given
by=m1v12/2+m2v22/2.
                                                       Â
=[(7.2)(102)/2]+[(19)(5.42)/2].
                                   Â
:.K.E.=360+277.02
                                  Â
:.K.E=637.02J.
3.change in kinetic energy
is=m1v12/2+m2v22/2.
                                         Â
=[(7.2)(102)/2]+[(19)(4.72)/2].
                              Â
:.K.E=360+209.855
                           Â
:.K.E.=569.855J.
