A 62.0 mL sample of a 0.122 M potassium sulfate solution is mixed with 36.5 mL...

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Chemistry

A 62.0 mL sample of a 0.122 M potassium sulfate solution ismixed with 36.5 mL of a 0.108 M lead(II) acetate solution and thefollowing precipitation reaction occurs:K2SO4(aq)+Pb(C2H3O2)2(aq)→2KC2H3O2(aq)+PbSO4(s) The solid PbSO4 iscollected, dried, and found to have a mass of 0.992 g . Determinethe limiting reactant, the theoretical yield, and the percentyield.

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3.7 Ratings (301 Votes)
no of mole molarity volume ofsolution in literno of mole of potassium sulphate 0122 0062 0007564moleno of mole of leadll acetate 0108 00365 0003942 moleAccording to reaction    See Answer
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