A 500 mL saturated solution of MgCO3 (MM = 84.3 g/mol) is reduced to 120 mL...

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Chemistry

A 500 mL saturated solution of MgCO₃ (M_M =84.3 g/mol) is reduced to 120 mL by evaporation. What mass of solidMgCO₃ is formed? K_sp = 4.0 x 10^-5for MgCO₃.

EDIT: If ions can evaporate in water then the answer below isright. If not, this is how I solved the problem.

MgCO₃ dissolves at a 1:1 ratio, thereforeK_sp=s² and s=K_sp^1/2 (orsqrt of Ksp)
s = (4.0x10^-5)^1/2 = .00632 M
Using the equationM₁V₁=M₂V₂
M₁ = s = 0.00632; V₁ = 0.500; V₂ = 0.120
Solving for M₂ = 0.0263 M
Then multiply M₂ by M_M to get the mass.

Therefore, mass = (0.0263)(84.3) = 2.22g

Can anyone confirm this?

Answer & Explanation Solved by verified expert

4.4 Ratings (767 Votes)

The part about solubility of MgCO3 s 000632 M is absolutely correct This solubility remains constant and does not depend upon volume of solution So whether the solution has volume 500 mL See Answer

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