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A 50 mL solution of 0.02500 M maleic acid (ka1=1.3e-2, ka2=5.9e-7) was titrated with 0.100 M...

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Chemistry

A 50 mL solution of 0.02500 M maleic acid (ka1=1.3e-2,ka2=5.9e-7) was titrated with 0.100 M NaOH. Calculate the pH afterthe adiition of a) 0.00 mL, b) 9.00 mL, c) 12.50 mL, d) 20.00 mL,e) 25.00 mL, and f) 26.00 mL of NaOH

Answer & Explanation Solved by verified expert
3.8 Ratings (543 Votes)
mmol of acid MV 500025 125 mmol of acid so 1252 250 mmol of H a initially Ka1 HHAH2A 13102 xx0025x x 001266 for 2nd ionization youmay assume this is mainly H1 so pH    See Answer
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