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  3. a 3.10 g sample of methane, ch4, is combusted in a

A 3.10 g sample of methane, CH4, is combusted in a calorimeter. The calorimeter and water...

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Chemistry

A 3.10 g sample of methane, CH4, is combusted in a calorimeter.The calorimeter and water combined have a heat capacity of 42.30kJ/K. The observed temperature rise is 4.05 °C. Calculate the heatof combustion of methane in kJ/mol. The products of the reactionare water and carbon dioxide.

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3.6 Ratings (464 Votes)

Answer – We are given, mass of methane = 3.10 g , change in temperature, Δt = 4.05oC

Heat capacity, C = 42.30 kJ/K

We know the heat of this reaction

q = C * Δt

   = 42.30 kJ/K * 4.05 oC

   = 171.31 kJ

Now we need to calculate the moles of methane

Moles of methane = 3.10 g / 16.04 g.mol-1

                              = 0.193 moles

So heat of combustion of methane = 171.3 kJ/0.193 mol

                                                         = 886.4 kJ/mol
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