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A 25.00 mL aliquot of a 0.100 M maleic acid, HOOC-CH=CH-COOH (pK1=1.87) and (pK2 = 6.23)...

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Chemistry

A 25.00 mL aliquot of a 0.100 M maleic acid, HOOC-CH=CH-COOH(pK1=1.87) and (pK2 = 6.23) was titrated with 0.1000 M NaOH.Construct a titration curve by calculating pH at a) initial pH b)after adding 5.00 mL of NaOH c) after adding 24.90 mL of NaOH d) atequivalence point e) after adding 25.01 mL of NaOH f) after adding25.50 ml of NaOH g) after adding 49.90 mL NaOH h) after adding50.00 mL NaOH i) after adding 50.01 mL NaOH j) after adding 51.00mL of NaOH

Answer & Explanation Solved by verified expert
4.1 Ratings (709 Votes)
This is a very long question however I will give you some guidance to do this First we need to calculate the equivalence volume at the equivalence point Vb 01 25 01 25 mL then    See Answer
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