A 240 V DC shunt motor draws 40 A while driving a constant torque load. The...

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Electrical Engineering

A 240 V DC shunt motor draws 40 A while driving a constanttorque load. The armature resistance is Ra = 0.2 â„¦, the fieldresistance is Rf = 240 â„¦ and machine constant is Ka = 120. The partof magnetization characteristic (field flux versus field current)related to the question is:
If (A) : Â Â Â Â Â 0.70 0.80 0.86 0.90 1.001.10 1.20 1.30 1.40
Ï• (mWb) : 5.80 6.30 6.59 6.70 7.20 7.60 7.96 8.20 8.45
The constant rotational loss is 240 W and the armature reactionis neglected. Find
a. the internal torque developed by the motor
b. speedÂ Â Â Â
c. efficiencyÂ Â Â Â

Answer & Explanation Solved by verified expert

4.2 Ratings (458 Votes)

As per question following values are givenTerminal voltage V 240 VMotor current I 40 AArmature resistance Ra 02 ohmField resistance Rf 240 ohmMachine constant Ka 120Rotational losses Pr 240 WaCurrent drawn by See Answer

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