components of the initial velocity is given as :
on horizontal, Vix = Vi Cos
400Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
  { eq. 1 }
where, Vi = 10.67 m/s
Vix = (10.67 m/s) (0.766)
Vix = 8.17 m/s
on vertical, Viy = Vi Sin
40Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
{ eq. 2 }
Viy = (10.67 m/s) (0.642)
Viy = 6.85 m/s
using equation of motio,
Vix2 = Viy2 + 2
as                          Â
{ eq. 3 }
inserting the values in above eq.
(8.17)2 = (6.85)2 + 2 (9.8) s
66.74 = 46.92 + 19.6 s
19.6 s = 19.82 m
s = 10 m
