a 2.00 mL sample of vinegar is titrated with 15.86 mL of 0.350 M NaOH to...

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a 2.00 mL sample of vinegar is titrated with 15.86 mL of 0.350M NaOH to a phenolphthalein end point

A) calculate the molar its of acetic acid in the vinegarsolution

B) calculate the % of acetic acid in the vinegar

Answer & Explanation Solved by verified expert

4.4 Ratings (583 Votes)

The reaction between Acetic acid and sodium hydroxide is given by

CH₃COOH + NaOH âŸ¶ CH₃COONa + H₂O

Â Â Â Â Â Â 1mole of CH₃COOH = 1mole of NaOH

CH₃COOH solutionÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â NaOH solution

M₁ = molarity of CH₃COOH ?Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â M₂ = Molarity of NaOH=0.35M

V₁ =Volume of CH₃COOH =2 mL Â Â Â Â Â Â Â Â Â Â Â Â V₂ = Volume of NaOH used=15.86mL

n₁ = 1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â n₂ = 1 (From equation)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â M₁ =

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â M₁ =

Molarity of Aceticacid in vinegar, M₁ = 2.775 M

Strength of CH₃COOH solution = Molarity x Molecular mass

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 2.775 X 60.06= 166.66 g/lit.

% of CH₃COOH in 2.0 mL of Vinegar solution = Strength x

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 166.66 X 0.002 X 100

% of CH₃COOH in 2.0 mL of Vinegar solution = 33.33%

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a 2.00 mL sample of vinegar is titrated with 15.86 mL of 0.350 M NaOH to...

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90.2K

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Chemistry

a 2.00 mL sample of vinegar is titrated with 15.86 mL of 0.350M NaOH to a phenolphthalein end point

A) calculate the molar its of acetic acid in the vinegarsolution

B) calculate the % of acetic acid in the vinegar

Answer & Explanation Solved by verified expert

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a 2.00 mL sample of vinegar is titrated with 15.86 mL of 0.350 M NaOH to...

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Verified Solution

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Chemistry

a 2.00 mL sample of vinegar is titrated with 15.86 mL of 0.350M NaOH to a phenolphthalein end pointA) calculate the molar its of acetic acid in the vinegarsolutionB) calculate the % of acetic acid in the vinegar

Answer & Explanation Solved by verified expert

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a 2.00 mL sample of vinegar is titrated with 15.86 mL of 0.350M NaOH to a phenolphthalein end point

A) calculate the molar its of acetic acid in the vinegarsolution

B) calculate the % of acetic acid in the vinegar