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A 110.1 gram sample of an unknown substance (MM = 189.50 g/mol) is cooled from 233.0...

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Chemistry

A 110.1 gram sample of an unknown substance (MM = 189.50 g/mol)is cooled from 233.0 °C to 147.6 °C. (heat capacity of liquid =1.62 J/g･°C; heat capacity of gas = 1.04 J/g･°C; ∆Hvap = 78.11kJ/mol; Tb = 160.3 °C)

A. How much energy (in kJ) is absorbed/released to cool thegas?

B. How much energy (in kJ) is absorbed/released to condense thegas?

C. How much energy (in kJ) is absorbed/released to cool theliquid?

D. What is the total amount of energy that must beabsorbed/released for the entire process?

Answer & Explanation Solved by verified expert
3.8 Ratings (649 Votes)
The unknown substance is cooled from 2330C to 1476C The entire process consists of the following subprocesses A Cooling the gas from 2330C to 1603C B Condensation of the gas at its boiling point Tb 1603C C Cooling the liquid from 1603C to 1476C A Heat capacity of the gas 104 JgC    See Answer
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