A 10.0 mL solution of 0.030 M AgNO3 was titrated with 0.015 M NaBr in the...

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A 10.0 mL solution of 0.030 M AgNO3 was titrated with 0.015 MNaBr in the cell. S.C.E. || titration solution | Ag(s) Find thecell voltage for 0.4, 10.0, 20.0, and 27.0 mL of titrant. (The Kspof AgBr = 5.0 ✕ 10−13.) 0.4 V 10.0 V 20.0 V 27.0 V

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a 04 ml of 0015 M NaBr added moles of AgNO3 003 M x 001 L 3 x 104 mols moles of NaBr 0015 M x 0004 L 6 x 105 mols excess AgNO3 24 x 104 mols Ag    See Answer
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