A 1 00 L flask is filled with 1 45 g of argon at 25 C A sampleof etha...

A 1.00 L flask is filled with 1.45 g of argon at 25 âˆ˜C. A...

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A 1.00 L flask is filled with 1.45 g of argon at 25 âˆ˜C. A sampleof ethane vapor is added to the same flask until the total pressureis 1.450 atm .
What is the partial pressure of ethane, Pethane, in the flask?Express your answer to three significant figures and include theappropriate units.

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4.1 Ratings (723 Votes)

A:- From the ideal gas equation, PV = nRT we have to solve this problem as,

=> Partial pressure of argon, P_argon = nRT / V

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = ((1.45 g Ar) / (39.9480 g Ar/mol)) x (0.08206 Lâ€‰atm/Kâ€‰mol) x (25 + 273.15)K / (1.00 L)
Partial pressure of argon, P_argon =0.888 atm

=> Partial pressure of ethane, P_ethane = P_total - P_argon

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = (1.450 - 0.888)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â P_ethane = 0.562 atm

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