A 10.0 gram bullet collides with a motionless 1.00 kilogram block of wood and becomes imbedded in...

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Physics

A10.0 gram bullet collides with a motionless 1.00 kilogram block ofwood and becomes imbedded in the block. The block is suspended fromabove by strings which are 1.00 meter long (ignore the mass of thestrings). After the collision the block swings to a point where theangle formed by the strings is 25.0 degrees to the vertical. a)what is the potential of the block/bullet combination relative toits original position? b) what is the kinetic energy of theblock/bullet combination just after the collision? c) what is thevelocity of the block/bullet combination just after the collision?d) what is the velocity of the bullet just before the collision? e)how much work did the bullet do on the block?

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4.3 Ratings (651 Votes)

aL length of the string 1 m angle moved 25 degh height gained above the original position L 1 Cosh 1 1 Cos25h 0094 mPotential energy gained is See Answer

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