A 10 L adiabatic container contains 0.1 mol of air, at a temperature of 250 K....

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Mechanical Engineering

A 10 L adiabatic container contains 0.1 mol of air, at atemperature of 250 K. It is closed by a stopcock. Ambient air is at300 K at a pressure of 1 bar. The stopcock is opened for a momentand a certain amount of air penetrates into the container. Afterthermal equilibrium is reached inside the container, the gastemperature is measured to be 350 K. 1) Assuming that the airbehaves as an ideal gas, find the initial pressure in thecontainer, the number of moles of air that penetrated in thecontainer, the sum of the internal energy changes for the gasinside the container and the gas that entered it and the finalpressure inside. 2) Find the enthalpy and entropy changes of thegas that is inside the container at the end of the process. Use κ =Cp,mol/CV,mol = 7/5 and Cp,mol − CV,mol = R.

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P pressure V Volume T temperature 1 2 0 are initial final and ambient condition respectively let P1 is the initial pressure of an adiabatic container Other Initial properties V1 10 L 001 m3 n1 01 mol T1 250 K according to Ideal gas equation P1 V1 n1RT1 P1 001 01 8314 250 initial pressure P1 20785 Nm2 Here total energy inside the container is always internal    See Answer
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