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A 10 cm long thin glass rod uniformly charged to +10 nC and a 10 cm...

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Physics

A 10 cm long thin glass rod uniformly charged to +10 nC and a 10cm long thin plastic rod uniformly charged to -10nC are placed sideby side 4 cm apart.

a. Find the electric field at distances 1.0 cm, 2.0 cm and 3.0cm from the glass rod along the line connecting the midpoints ofthe two rods. (Hint: treat the rods as a uniform line ofcharges.)

b. If the plastic rod is exchanged for a glass rod of the samesize uniformly charged to +10 nC, what is the new electric field at1.0 cm, 2.0 cm and 3.0 cm?

Answer & Explanation Solved by verified expert
4.0 Ratings (440 Votes)
GivenLength of the rod L 10 cm 010 mThe magnitude of charge on glass rod Q 10 x 109CSolutionA1At D 1 cm 001 mElectric field due to glass rodEg kQDDLEg 9 x 109 x 10 x 109 001001 01Eg 82 x 104 NC towards rightPoint A is at distance 3 cm from plastic rodr 4 Dr 41 3 cm 003 mElectric field due to plastic rodEp KQrrLEp 9 x 109 x 10 x109 003003 01Ep 23 x 104 NC towards rightTotal FieldE Eg EpE 82 x 104 23 x 104E 105 x 104 Nc    See Answer
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