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  3. a 1 liter solution contains 0.382 m hydrofluoric a

A 1 liter solution contains 0.382 M hydrofluoric acid and 0.509 M sodium fluoride. Addition of...

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Chemistry

A 1 liter solution contains 0.382 M hydrofluoric acid and 0.509M sodium fluoride. Addition of 0.191 moles of sodium hydroxidewill: (Assume that the volume does not change upon the addition ofsodium hydroxide.) Raise the pH slightly, Lower the pH slightly,Raise the pH by several units, Lower the pH by several units, Notchange the pH ,Exceed the buffer capacity

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4.2 Ratings (740 Votes)

no of moles of HF = molarity * volume in L

                            = 0.382*1 = 0.382moles

no of moles of NaF   = molarity * volume in L

                               = 0.509*1 =- 0.509moles

PH   = Pka + log[NaF]/[HF]

      = 3.17+ log0.509/0.382

      = 3.17+ 0.1246 = 3.2946

by the addition of 0.191 moles of NaOH

no of moles of HF = 0.382-0.191 = 0.191moles

no of moles of NaF = 0.509+0.191 = 0.7 moles

PH   = Pka + log[NaF]/[HF]

      = 3.17 + log0.7/0.191

      = 3.17+ 0.564   = 3.734

Raise the pH slightly

  
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