A 0.7221g sample of a new compound has been analyze and found to contain the following...

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Chemistry

A 0.7221g sample of a new compound has been analyzeand found to contain the following masses of elements : Carbon0.2990g, hydrogen 0.05489g, nitrogen 0.2318g, and Oxygen0.1328g.
call ate the empirical formula of the compound

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4.1 Ratings (564 Votes)

Carbon = 0.2990g = 0.2990g / (12g/mol) = 0.025 mol,

Hydrogen = 0.05489g = 0.05489g / (1.0 g/mol) = 0.05489 mol

nitrogen = 0.2318g = 0.2318g/ (14.0 g/mol) = 0.0166 mol ,

Aand Oxygen 0.1328g = 0.1328g/ (16.0 g/mol) = 0.0083 mol.

The molar ratio of = Carbon:hydrogen : nitrogen: Oxygen = 0.025 : 0.05489: 0.0166: 0.0083

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 1 : 2.12 : 0.66 : 0.33

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 3.03 : 6.42 : 2 : 1

So, the empirical formula of the compound is C₃H₆O₂N

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