Carbon = 0.2990g = 0.2990g / (12g/mol) = 0.025 mol,
Hydrogen = 0.05489g = 0.05489g / (1.0 g/mol) = 0.05489 mol
nitrogen = 0.2318g = 0.2318g/ (14.0 g/mol) = 0.0166 mol ,
Aand Oxygen 0.1328g = 0.1328g/ (16.0 g/mol) = 0.0083 mol.
The molar ratio of = Carbon:hydrogen : nitrogen: Oxygen = 0.025
: 0.05489: 0.0166: 0.0083
                                                                                                      Â
= 1 : 2.12 : 0.66 : 0.33
                                                                                                     Â
= 3.03 : 6.42 : 2 : 1
So, the empirical formula of the compound is
C3H6O2N