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A 0.450-gram sample of impure CaCO3(s) is dissolved in 50.0 mL of 0.150 M HCl(aq). The...

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Chemistry

A 0.450-gram sample of impure CaCO3(s) is dissolved in 50.0 mLof 0.150 M HCl(aq). The equation for the reaction is:

CaCO3(s) + 2 HCl(aq) ?CaCl2(aq) + CO2(g) +H2O(l)

The excess HCl(aq) is titrated by 7.65 mL of 0.125 M NaOH(aq).Calculate the mass percentage of CaCO3(s) in the sample.

Answer & Explanation Solved by verified expert
3.6 Ratings (446 Votes)
765 mL of 0125 M NaOH765 X0125 mmoles of NaOH 0956 mmoles of NaOH which    See Answer
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