A 0.4423 g sample of pewter, containing tin, lead, copper, and zinc, was dissolved in acid....

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A 0.4423 g sample of pewter, containing tin, lead, copper, andzinc, was dissolved in acid. Tin was precipitated as SnO2·4H2O andremoved by filtration. The resulting filtrate and washings werediluted to a total volume of 200.0 mL. A 15.00 mL aliquot of thissolution was buffered, and titration of the lead, copper, and zincin solution required 35.87 mL of 0.001481 M EDTA. Thiosulfate wasused to mask the copper in a second 20.00 mL aliquot. Titration ofthe lead and zinc in this aliquot required 33.95 mL of the EDTAsolution. Finally, cyanide was used to mask the copper and the zincin a third 25.00 mL aliquot. Titration of the lead in this aliquotrequired 25.03 mL of the EDTA solution. Determine the percentcomposition by mass of each metal in the pewter sample

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4.0 Ratings (520 Votes)
EDTA form 11 complex with copper lead and Zinc so the total amount of copper lead zince in 200 mL of the solution in which the 04423 g of sample after removing tin was dissolved was    See Answer
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