A 0.042 kg aluminum bullet traveling at 456 m/s strikes an armor plate and comes to...

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A 0.042 kg aluminum bullet traveling at 456 m/s strikes an armorplate and comes to a stop. If all its energy is converted to heatthat is absorbed by the bullet, what is the bullet's temperaturechange in degrees Celsius? (This is a multi-step problem.)

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4.2 Ratings (760 Votes)

Given data

mass of bullet m= 0.042 kg

velocity of bullet v= 456 m/s

now here energy conserved so the kinetic energy of the bullet is (k.e) is converted in to heat energy results the change in temperature of the bullet

so k.e= 1/2*m*v^2Â Â Â => 1/2*0.042*456^2 =4366.656 J

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 4366.656*0.239 cal =1043.630 cal

now from the relationÂ Â dQ= m*C*dtÂ Â Â Â Â C is the specific heat of alluminium 0.22 Kcal/kg C= 220 cal/kg C

now change in temperature isÂ Â dt= dQ/m*CÂ Â Â => dt= 1043.630/(0.042*220) = 112.946 celcius

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