60.0 mL of 0.100M KOH(aq) is mixed with 40.0 mL of 0.250M HCl(aq) at 25 oC....

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60.0 mL of 0.100M KOH(aq) is mixed with 40.0 mL of 0.250MHCl(aq) at 25 oC. Assuming that volumes are additive, the pH ofresulting solution is

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mmol KOH concentrationVolume 0100 M 600 ml 600 mmolmmol HCl concentrationVolume 0250 M 400 ml 100    See Answer
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