500kgh-1 of a 10% w/w solutionof a compoun X(OH)2 is to be treated using a 5%...

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500kgh-1 of a 10% w/w solutionof a compoun X(OH)2 is to betreated using a 5% excess of 20% w/w solution of Na2CO3 toprecipitate the X as its carbonate according to the balancedreaction equation: X(OH)2 + Na2CO3 ------> XCO3 + 2NaOH All thesolid is filtered off but some solution remains with the solid suchthat the solution forms 4% w/w of the total mass removed. thefiltered liquid product is then neutralised with 2 molarhydrochloric acid according to the reactions NaCO3 + 2HCl ----->2NaCl + H2O + CO2 NaOH + HCl -----> NaCl + H2O Calculate: 1. theamount (kgh-1) of sodium carbonate solution required. 2. the amount(kgh-1) and composition (%w/w) of the solid product afterfiltration 3. the amount (kgh-1) and composition (%w/w) of thesolid product after filtration. 4. the amount of acid (in litresper hour) required for neutralisation data: Relative atomic mass ofX= 40, O=16, H=1, Na= 23, C= 12, Cl= 35.5

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3.7 Ratings (536 Votes)
weight of solution 500 10100 50 kghr molar mass of XOH2 74 Moles of XOH2 50100074 67567 gm moleshr According to the reaction XOH2 Na2CO3XCO3 2NaOH moles of Na2CO3 required 67567    See Answer
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