30.0 mL solution of 0.010 M piperidine (the active ingredient in
hot pepper, the protonated form...
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Chemistry
30.0 mL solution of 0.010 M piperidine (the active ingredient inhot pepper, the protonated form is a monoprotic weak acid with pKa=11.123) was titrated with 0.050 M HCl.  a) Find Ve (thevolume of HCl at equivalent point); b) Calculate the pH at Va (thevolume of HCl added) =0, ¼ Ve, Ve, and 1.1 Ve; c) Using theinformation from (b), sketch the titration curve for thistitration. Please mark the “landmark†points on this curve.
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a when Volume of HCl 0mL There will be only piperidine B in the solution It will hydrolyze as B H2O BH OH Initial 001 0 0 Change x x x Equilib 001x x x Kb Kw Ka pKa 11123 pKb 14 pKa 14 11123 2877 Kb antilog 2877 133 X 103 Kb OH BH B x2 001x 133 X 103 x2 00000133 000133x x2 00000133 000133x 0 x 003 M OH pOH logOH
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