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  3. 3 a 5 0 given that the eigenvalue 3 is defective a

3 a 5 0 Given that the eigenvalue 3 is defective and the eigenvalue 5...

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Algebra

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3 a 5 0 Given that the eigenvalue 3 is defective and the eigenvalue 5 is complete then a possible Jordan normal form of A is 310 0 03 0 0 00 0 0 0 5 30 0 03 0 0 00 50 0 0 0 5 31 0 0 03 1 0 00 5 1 000 5 10 0 0310 0 0 3 0 000 5 31 0 0 0300 00 50 0 5

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