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2)Rank the following titrations in order of increasing pH at the equivalence point of the titration...

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Chemistry

2)Rank the following titrations in order of increasing pH at theequivalence point of the titration (1 = lowest pH and 5 = highestpH). 100.0 mL of 0.100 M HC3H5O2 (Ka = 1.3 x 10-5) by 0.100 M NaOH200.0 mL of 0.100 M (C2H5)2NH (Kb = 1.3 x 10-3) by 0.100 M HCl100.0 mL of 0.100 M NH3 (Kb = 1.8 x1 0-5) by 0.100 M HCl 100.0 mLof 0.100 M KOH by 0.100 M HCl 100.0 mL of 0.100 M HNO2 (Ka = 4.0 x10-4) by 0.100 M NaOH

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3.8 Ratings (345 Votes)
First to all the pH at equivalence point of strong acid and base is in general terms 7 so the pH for KOH and HCl would be 7 For HC3H5O2 1000 mL of 0100 M HC3H5O2 Ka 13 x 105 by 0100 M NaOH makes 0100 moles NaC3H5O2 0200 litres 005 Molar C3H5O2 which    See Answer
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